跳到内容
Dictionary of cuisine. 预览资料
关闭预览资料
正在查...

Dictionary of cuisine.

著者: Alexandre Dumas
出版商: [New York] Simon and Schuster, 1958.
版本/格式:   打印图书 : 英语查看所有的版本和格式
评估:

(尚未评估) 0 附有评论 - 争取成为第一个。

主题
更多类似这样的

 

在图书馆查找

&AllPage.SpinnerRetrieving; 正在查找有这资料的图书馆...

详细书目

类型/形式: Dictionaries
附加的形体格式: Online version:
Dumas, Alexandre, 1802-1870.
Dictionary of cuisine.
[New York] Simon and Schuster, 1958
(OCoLC)685201388
文档类型 图书
所有的著者/提供者: Alexandre Dumas
OCLC号码: 1426478
描述: vi, 282 pages illustrations 23 cm
责任: Edited, abridged, and translated by Louis Colman, from Le grand dictionnaire de cuisine. Illus. by John H. Jacoby.

评论

用户提供的评论
正在获取GoodReads评论...
正在检索DOGObooks的评论

标签

争取是第一个!
确认申请

你可能已经申请过这份资料。如果还是想申请,请选确认。

链接数据


Primary Entity

<http://www.worldcat.org/oclc/1426478> # Dictionary of cuisine.
    a schema:Book, schema:CreativeWork ;
    bgn:translationOfWork <http://www.worldcat.org/title/-/oclc/1426478#CreativeWork/unidentifiedOriginalWork> ;
    library:oclcnum "1426478" ;
    library:placeOfPublication <http://id.loc.gov/vocabulary/countries/nyu> ;
    library:placeOfPublication <http://dbpedia.org/resource/New_York_City> ; # New York
    schema:about <http://experiment.worldcat.org/entity/work/data/2908440975#Topic/food_dictionaries_french> ; # Food--Dictionaries--French
    schema:about <http://experiment.worldcat.org/entity/work/data/2908440975#Topic/food_french> ; # Food--French
    schema:about <http://dewey.info/class/641.03/> ;
    schema:about <http://id.worldcat.org/fast/1754966> ; # Cooking
    schema:about <http://experiment.worldcat.org/entity/work/data/2908440975#Topic/cookery_dictionaries_french> ; # Cookery--Dictionaries--French
    schema:about <http://experiment.worldcat.org/entity/work/data/2908440975#Topic/cooking_french> ; # Cooking--French
    schema:about <http://id.worldcat.org/fast/930458> ; # Food
    schema:bookFormat bgn:PrintBook ;
    schema:creator <http://viaf.org/viaf/51688902> ; # Alexandre Dumas
    schema:datePublished "1958" ;
    schema:exampleOfWork <http://worldcat.org/entity/work/id/2908440975> ;
    schema:genre "Dictionaries"@en ;
    schema:inLanguage "en" ;
    schema:isSimilarTo <http://www.worldcat.org/oclc/685201388> ;
    schema:name "Dictionary of cuisine."@en ;
    schema:productID "1426478" ;
    schema:publication <http://www.worldcat.org/title/-/oclc/1426478#PublicationEvent/new_yorksimon_and_schuster_1958> ;
    schema:publisher <http://experiment.worldcat.org/entity/work/data/2908440975#Agent/simon_and_schuster> ; # Simon and Schuster
    wdrs:describedby <http://www.worldcat.org/title/-/oclc/1426478> ;
    .


Related Entities

<http://dbpedia.org/resource/New_York_City> # New York
    a schema:Place ;
    schema:name "New York" ;
    .

<http://experiment.worldcat.org/entity/work/data/2908440975#Agent/simon_and_schuster> # Simon and Schuster
    a bgn:Agent ;
    schema:name "Simon and Schuster" ;
    .

<http://experiment.worldcat.org/entity/work/data/2908440975#Topic/cookery_dictionaries_french> # Cookery--Dictionaries--French
    a schema:Intangible ;
    schema:name "Cookery--Dictionaries--French"@en ;
    .

<http://experiment.worldcat.org/entity/work/data/2908440975#Topic/food_dictionaries_french> # Food--Dictionaries--French
    a schema:Intangible ;
    schema:name "Food--Dictionaries--French"@en ;
    .

<http://id.worldcat.org/fast/1754966> # Cooking
    a schema:Intangible ;
    schema:name "Cooking"@en ;
    .

<http://id.worldcat.org/fast/930458> # Food
    a schema:Intangible ;
    schema:name "Food"@en ;
    .

<http://viaf.org/viaf/51688902> # Alexandre Dumas
    a schema:Person ;
    schema:birthDate "1802" ;
    schema:deathDate "1870" ;
    schema:familyName "Dumas" ;
    schema:givenName "Alexandre" ;
    schema:name "Alexandre Dumas" ;
    .

<http://www.worldcat.org/oclc/685201388>
    a schema:CreativeWork ;
    rdfs:label "Dictionary of cuisine." ;
    schema:description "Online version:" ;
    schema:isSimilarTo <http://www.worldcat.org/oclc/1426478> ; # Dictionary of cuisine.
    .


Content-negotiable representations

关闭窗口

请登入WorldCat 

没有张号吗?很容易就可以 建立免费的账号.