skip to content
Foundations of classical analysis. Preview this item
ClosePreview this item
Checking...

Foundations of classical analysis.

Author: Georg Kreisel; Stanford University.
Publisher: [Stanford? Calif., [1964 or 5]
Edition/Format:   Book : Conference publication : EnglishView all editions and formats
Database:WorldCat
Rating:

(not yet rated) 0 with reviews - Be the first.

Subjects
More like this

 

Find a copy in the library

&AllPage.SpinnerRetrieving; Finding libraries that hold this item...

Details

Additional Physical Format: Online version:
Foundations of classical analysis.
[Stanford? Calif., [1964 or 5]
(OCoLC)707161279
Material Type: Conference publication
Document Type: Book
All Authors / Contributors: Georg Kreisel; Stanford University.
OCLC Number: 63617954
Notes: Caption title.
By G. Kreisel and others.
"In summer 1963 an informal seminar was at Stanford University to consider the current state of (constructive) foundations of classical analysis. Volume 1 of the present report contains material presented during the seminar. Volume 2 contains improvements obtained during the academic year 1963-64."
Description: 2 v. in 1. 28 cm.
Other Titles: Classical analysis, Foundations of.

Reviews

User-contributed reviews
Retrieving GoodReads reviews...
Retrieving DOGObooks reviews...

Tags

Be the first.

Similar Items

Related Subjects:(1)

Confirm this request

You may have already requested this item. Please select Ok if you would like to proceed with this request anyway.

Linked Data


<http://www.worldcat.org/oclc/63617954>
library:oclcnum"63617954"
library:placeOfPublication
library:placeOfPublication
rdf:typeschema:Book
rdf:valueUnknown value: cnp
rdfs:seeAlso
schema:about
schema:contributor
schema:contributor
schema:datePublished""
schema:exampleOfWork<http://worldcat.org/entity/work/id/47741004>
schema:inLanguage"en"
schema:name"Foundations of classical analysis."
schema:publication
wdrs:describedby

Content-negotiable representations

Close Window

Please sign in to WorldCat 

Don't have an account? You can easily create a free account.