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关于形成稳定核素的条件以及广义相对论引力场定律推论的硏究 = Conditions for formation of stable nuclides and the unification of four basic interreactions /
Guan yu xing cheng wen ding he su de tiao jian yi ji guang yi xiang dui lun yin li chang ding lü tui lun de yan jiu = Conditions for formation of stable nuclides and the unification of four basic interreactions

by 沈觐陶. Jintao Shen

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Results of discussed problems   (2012-10-04)

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by shenjintao

Results of discussed problems
• If this accelerator (CERN) adjust the colliding velocity of
particle or electron to V =0.86602540378 C,
n=1.15470053838(a medium with index of refraction n) and
fix it.At the same time make the colloiding energy variates
from 1u(Atomic mass unit=931.5016 Mev) to 100u or
1000u.What will it happen? It must produce any stable
nuclides or any desired elements as shown in periodic table.
That means : Human being can but know nature and
discover new phenomena but cannot produce it. That's an
old idea. Now we can make and produce any material,if we
know how to create the the stable nuclides. May be free
from resource deficient,the energy
resources,coal,oil,metals and other mineral resources.
Because it can be created manually.
Whenβ=±0.86602540378,m=+ (matter)。When
β=±0.9682458366,m=- (antimatter)。
• Design the superconductive material under any desired
purpose. If the power supply is E=0.5E+6 ev. The
temperature in wire (or cable) keep at 273 K and less
energy consumption.The mass number of superconductive
material must be A=7606 u, the index of reflection n
=1.133980405, csm = 3.9163733E-4, β= 0.862860695, βcr
=0.881849453, β≤βcr.
• The Treatment Of Cancer By Heavy Ion Beam. Through
accelerator ion can obtain some definite high energy and
forms useable heavy ion beam for radiotherapy.Heavy ion
beam of definite energy travels definite distance in matter.
It excites and ionizes the atom in matter and consumes
energy itself .Choose 4Be9 ,E= 3.966378964Gev it will
produce the maximum RBE and the best therapeutic
efficiency.βBe= 0.7340200589 ≤1/1.33(0.7518796992).
Use any other heavy ion its velocity β is far less than βcr.
• About 3K Microwave Background Radiation On Celestial
Body sun=8,204.83K.mercury:far point=0.362K,near
point=0.356K. venus:far point=2.3K,near point=2.24K. earth;
far point= 2.75 K, near point=2.64K. mars:far
point=0.568K,near point=0.535K.jupiter:far
point=84.315K,near point=68.37K.saturn;far
point=32.311K,near point=21.685K. uranus:far
point=13.013K,near point=4.78K. neptune:far
point=17.601K,near point=5.24K. moon:far
point=0.124K,near point=0.124K.
• Utilize Terrestrial Heat for producing electric power: The
terrestrial heat discussed in this paper is only caused by
the pressure of earth's crust (except volcanoes).
3.1KmTerrestial heat=17 C. 3.2KmTerrestial heat=56.6 C.
3.3KmTerrestial heat=99.8 C. 3.4KmTerrestial heat=147 C.
3.5KmTerrestial heat=198.7 C.3.6KmTerrestial heat=255 C.
3.7KmTerrestial heat=316 C. 3.8KmTerrestial heat=382.5 C.
3.9KmTerrestial heat=454.3 C. 4KmTerrestial heat=531.8C.
4.1KmTerrestial heat=615.3 C. 4.2KmTerrestial heat=705.2
C. 4.3KmTerrestial heat=801.8C. 4.4KmTerrestial
heat=905.3 C.
• Discuss the constant of light velocity In solar system. The
light velocity which measured on earth is known and it can
be treated as a constant for the stellar system its own. But
in different stellar system which relate to earth has
different value of C. The light velocity on different celestial
body are as follows:cm/s sun :Near(Far)
Point=3.0568723940E+10. mercury:
3.0806404630E+10(3.0336461040E+10).
venus :3.1017465250E+10(3.0138911880E+10).
earth:3.1194400550E+10 (2.9979245800E+10). mars :
3.1537640150E+10 (2.9683952580E+10). jupiter :
3.4319006510E+10(2.7828727690E+10).
saturn :3.8787811220E+10(2.6032237450E+10).
uranus :6.2676068610E+10(2.3028153200E+10). neptune :
6.9373890180E+10(2.0636832590E+10).
pluto :4.0572495580E+10(1.9076918890E+10).
moon :2.9980718420E+10(2.9977773380E+10).
• The Mass Of Photon: Photon- A New Energy Source. The
mass of photon may be 0 or may be any value. According to
mass equation,m = A ( 2 - βn ) when βn =2 , mphoton = 0.
when electron-positron pair collide in velocity
β= .942809038 will produce photon of mass m photon =
1.38251057E-34(g) and release heat energy of 600K. give
out the following data of different temperature: 3.65E-
9K,mphoton =8.4102726E-46g, β
=0.94280904158,n=2.12132034356. 1.24K,mphoton
=2.8571885E-37g, β=0.94280904157,n=2.12132034341
20K,mphoton =4.6083685E-36g, β=0.94280904148,
n=2.1213203411 300K,mphoton =6.9125528E-35g,
β=0.94280904009,n=2.1213203067 1,000K,mphoton=
2.3041842E-34g, β=0.94280903661, n=2.1213202206.
• The Interreaction Of Photon (particles) And Matter.
Calculate the requisite energy of electron-beam for getting
desired temperature in solid, liquid, and gas. (1) Require the
necessary energy for reaching 3000 K in Aluminium
Al(27),Ei = 1.5822333e-7
erg,β=0.5456039552,n=0.354205601,equivalent to 100 KV.(2)
To heat water(H2O) TO 400 K,Ei= 4.7173083E-8 erg, β=
0.3255606748,n=0.1769802208. It is equivalent to 40 KV. (3)
To heat atmospreric temperature to 400 K, Ei =
4.160274913E-8 erg, β= 0.03072058397,n=0.1654074122. It
is equivalent to 30 KV.
• The Mass Equation : the atomic mass of stable nuclide will
be m = A ( 2 - βn ) (u) Where m is expressed in atomic mass
unit u. A is the mass number and is expressed in atomic
mass unit u. According to condition 1(1), m must be an
integral multiple of atomic mass unit. When βn=1, m=A.the
stable realm of β is between 0.864969723 to 0.867062715.
Matter And Antimatter:Matter forms at β≤0.9428090416 and
antimatter forms at β≥ 0.9428090416. So, b cr
=0.9428090416.
• The Gravitation Center - There is a Block Hole in Solar
System. The gravitation center which forms the solar
system exist at a distance of 3.913022133E+14 cm from
earth. At a position between Neptune and Uranus.
7.3074E+13 cm to Neptune and 8.9526E+13 to Uranus. The
mass of the gravitation center(or black hole) is
5.271056516E+42 g. which is 2.64E+9 times larger than the
mass of Sun.

这次火星探测器有没有探测:
1。火星的重力加速度。cm/s2 地球是980.7252 火星是377.0385
2. 3 度k 微波辐射地球是far point= 2.75 K, near
point=2.64K. 火星是far point=0.568K,near
point=0.535K.
3. 火星上的光速cm/ s 地球是Near Point 3.1194400550E+10
Far Point 2.9979245800E+10
火星是Near Point 3.1537640150E+10
FarPoint 2.9683952580E+10
4. first cosmic speed escape velocity Km/s
7.9091 11.1851 earth
3.5759 5.0571

 

Utilize Terrestrial Heat for producing electric power:
The terrestrial heat discussed in this paper is only
caused by the pressure of earth's crust (except
volcanoes).
3.1KmTerrestial heat=17 C.
3.2KmTerrestial heat=56.6 C.
3.3KmTerrestial heat=99.8 C.
3.4KmTerrestial heat=147 C.
3.5KmTerrestial heat=198.7 C.
3.6KmTerrestial heat=255 C.
3.7KmTerrestial heat=316 C.
3.8KmTerrestial heat=382.5 C.
3.9KmTerrestial heat=454.3 C.
4KmTerrestial heat=531.8C.
4.1KmTerrestial heat=615.3 C.
4.2KmTerrestial heat=705.2C.
4.3KmTerrestial heat=801.8C.
4.4KmTerrestial heat=905.3 C.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图书馆有藏书。

 

The Treatment Of Cancer By Heavy Ion Beam. Through
accelerator ion can obtain some definite high energy
and forms useable heavy ion beam for radiotherapy.Heavy
ion beam of definite energy travels definite distance
in matter.It excites and ionizes the atom in matter and
consumes energy itself .Choose 4Be9 ,E= 3.966378964Gev
it will produce the maximum RBE and the best therapeutic
efficiency.βBe= 0.7340200589 ≤1/1.33(0.7518796992).
Use any other heavy ion its velocity β is far less than
βcr.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图
书馆有藏书

 

To obtain the so called “ Higgs boson”
To obtain the so called “ Higgs boson” .the
colliding velcity of electron or particle must be
V =0.86602540378 C, n=1.15470053838(a
medium with index of refraction n) and fix it. At
the same time the colliding energy must be an
integral multiple of atomic mass unit
1u(Atomic mass unit=931.5016 Mev) to 100u
or1000u. say134u ,135u.(124.82121Gev or
125.75271Gev}.

 

The Mass Of Photon: Photon- A New Energy Source. The
mass of photon may be 0 or may be any value. According
to
mass equation,m = A ( 2 - βn ) when βn =2 , mphoton =
0.
when electron-positron pair collide in velocity
β= .942809038 will produce photon of mass m photon =
1.38251057E-34(g) and release heat energy of 600K. give
out the following data of different temperature: 3.65E-
9K,mphoton =8.4102726E-46g, β
=0.94280904158,n=2.12132034356. 1.24K,mphoton
=2.8571885E-37g, β=0.94280904157,n=2.12132034341
20K,mphoton =4.6083685E-36g, β=0.94280904148,
n=2.1213203411 300K,mphoton =6.9125528E-35g,
β=0.94280904009,n=2.1213203067 1,000K,mphoton=
2.3041842E-34g, β=0.94280903661, n=2.1213202206.

 

The relative position of gravitation center and solar system are shown
as follows:
Gravitation
center Sun earth Uranus Neptune
Neptune Uranus x 2.8683E+14 cm x x 1.626E+14 x 7.3074E+13x 8.9526E+13 x
     
x 3.763562133E+14 cm x 1.4946E+13 cm x
x 3.91302213323E+14 cm x
Fig.1
The distance from gravitation center to the celestial body of solar system.
r To Near Point cm Far Point cm
sun 3.7635621330E+143.7635621330E+14
mercury 3.7057121330E+143.8214121330E+14
venus 3.6554521330E+143.8716721330E+14
earth 3.6141021330E+143.9130221332E+14
mars 3.5358621330E+143.9912621330E+14
jupiter 2.9859621330E+144.5411621330E+14
saturn 2.3375621330E+145.1895621330E+14
uranus 8.9526213300E+136.6318621330E+14
neptune -7.3073786700E+13 8.2578621330E+14
pluto -2.1364378670E+14 9.6635621330E+14
moon -3.9126377330E+14 3.9134065330E+14

 

The Mass Of Photon: Photon- A New Energy Source. The
mass of photon may be 0 or may be any value. According
to
mass equation,m = A ( 2 - βn ) when βn =2 , mphoton =
0.
when electron-positron pair collide in velocity
β= .942809038 will produce photon of mass m photon =
1.38251057E-34(g) and release heat energy of 600K. give
out the following data of different temperature: 3.65E-
9K,mphoton =8.4102726E-46g, β
=0.94280904158,n=2.12132034356. 1.24K,mphoton
=2.8571885E-37g, β=0.94280904157,n=2.12132034341
20K,mphoton =4.6083685E-36g, β=0.94280904148,
n=2.1213203411 300K,mphoton =6.9125528E-35g,
β=0.94280904009,n=2.1213203067 1,000K,mphoton=
2.3041842E-34g, β=0.94280903661, n=2.1213202206.

 

The Interreaction Of Photon (particles) And Matter.
Calculate the requisite energy of electron-beam for
getting desired temperature in solid, liquid, and gas.
(1) Require the necessary energy for reaching 3000 K
in Aluminium
Al(27),Ei = 1.5822333e-7
erg,β=0.5456039552,n=0.354205601,equivalent to 100
KV.
(2)To heat water(H2O) TO 400 K,Ei= 4.7173083E-8 erg,
β= 0.3255606748,n=0.1769802208. It is equivalent to 40
KV.
(3) To heat atmospreric temperature to 400 K, Ei =
4.160274913E-8 erg, β= 0.03072058397,n=0.1654074122.
It is equivalent to 30 KV.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图书馆有藏书

 

The Mass Equation : the atomic mass of stable nuclide
will be m = A ( 2 - βn ) (u) Where m is expressed in
atomic mass unit u. A is the mass number and is expressed
in atomic mass unit u. According to condition 1(1), m
must be an integral multiple of atomic mass unit. When
βn=1, m=A.the stable realm of β is between 0.864969723
to 0.867062715.
Matter And Antimatter:Matter forms at β≤0.9428090416
and antimatter forms at β≥ 0.9428090416. So, b cr
=0.9428090416.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大

 

The Gravitation Center - There is a Block Hole in Solar
System. The gravitation center which forms the solar
system exist at a distane of 3.913022133E+14 cm from
earth. At a position between Neptune and Uranus.
7.3074E+13 cm to Neptune and 8.9526E+13 to Uranus. The
mass of the gravitation center(or black hole) is
5.271056516E+42 g. which is 2.64E+9 times larger than
the
mass of Sun.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)

 

The distance from gravitation center to the celestial body of solar system.
r To Near Point cm Far Point cm
sun 3.7635621330E+14 3.7635621330E+14
mercury 3.7057121330E+14 3.8214121330E+14
venus 3.6554521330E+14 3.8716721330E+14
earth 3.6141021330E+14 3.9130221332E+14
mars 3.5358621330E+14 3.9912621330E+14
jupiter 2.9859621330E+14 4.5411621330E+14
saturn 2.3375621330E+14 5.1895621330E+14
uranus 8.9526213300E+13 6.6318621330E+14
neptune -7.3073786700E+13 8.2578621330E+14
pluto -2.1364378670E+14 9.6635621330E+14
moon -3.9126377330E+14 3.9134065330E+14

 

C2= G M 
r 
Celestial Body C cm/ s Near Point C cm/ s Far Point
moon 2.9980718420E+10 2.9977773380E+10
Pluto 4.0572495580E+10 1.9076918890E+10
neptune 6.9373890180E+10 2.0636832590E+10
Uranus 6.2676068610E+10 2.3028153200E+10
saturn 3.8787811220E+10 2.6032237450E+10
jupiter 3.4319006510E+10 2.7828727690E+10
mars 3.1537640150E+10 2.9683952580E+10
Earth 3.1194400550E+10 2.9979245800E+10
venus 3.1017465250E+10 3.0138911880E+10
mercury 3.0806404630E+10 3.0336461040E+10
Sun 3.0568723940E+10 3.0568723940E+

 

If this accelerator (CERN) adjust the colliding
velocity of particle or electron to V =0.86602540378
C,n=1.15470053838(a medium with index of refraction n)
and fix it..At the same time make the colloiding energy
variates from 1u(Atomic mass unit=931.5016 Mev) to 100u
or 1000u.What will it happen? It must produce any stable
nuclides or any desired elements as shown in periodic
table. That means : Human being can but know nature and
discover new phenomena but cannot produce it. That's
an old idea. Now we can make and produce any material,if
we know how to create the the stable nuclides. May be
free from resource deficient,the energy
resources,coal,oil,metals and ther mineral
resources.Because it can be created manually.
Whenβ=±0.86602540378,m=+ (matter)。When
β=±0.9682458366,m=- (antimatter)。
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图书馆有藏书。

 

Design the superconductive material under any desired
purpose. If the power supply is E=0.5E+6 ev. The
temperature in wire (or cable) keep at 273 K and less
energy consumption.The mass number of superconductive
material must be A=7606 u, the index of reflection n
=1.133980405, csm = 3.9163733E-4, β= 0.862860695, βcr
=0.881849453, β≤βcr.

 

About the gravitational acceleration
① The gravitational acceleration of earth
gearth= G mearth / r2
earth = G 5.98E+27/ (6.3783E+8)2 = 980.7252 cm/s2
② The first cosmic speed and escape velocity of any matter relate to earth
Vsc
2 =  G Mearth/ rearth
Vescape
2 = 2G Mearth/ rearth
Celestial Body g = Gm/ r2 cm/s2 Vsc Km/s Vescape Km/s
sun 27,326.199 436.1082 616.7501
mercury 333.0662 2.8856 4.0809
venus 850.4891 7.2626 10.2694
earth 980.7252 7.9091 11.1851
mars 377.0385 3.5759 5.0571
jupiter 2,495.4592 42.1813 59.6534
saturn 1,071.9677 25.2551 35.7161
uranus 882.4725 15.0744 21.3184
neptune 1,103.957 16.5963 23.4707
pluto
moon 162.3808 1.6804 2.3765

 

About 3K Microwave Background Radiation On Celestial
Body
sun=8,204.83K.
mercury:far point=0.362K,near point=0.356K.
venus:far point=2.3K,near point=2.24K.
earth;far point= 2.75 K, near point=2.64K.
mars:far point=0.568K,near point=0.535K.
jupiter:far point=84.315K,near point=68.37K.
saturn;far point=32.311K,near point=21.685K.
uranus:far point=13.013K,near point=4.78K.
neptune:far point=17.601K,near point=5.24K.
moon:far point=0.124K,near point=0.124K.
Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图书馆有
藏书。

 

2012-7-6
希格斯玻色子是一个在粒子物理标准模型中设想的基本粒子,该粒子也被喻为
“上帝粒子”,是宇宙万物的质量之源。
在去年进行的粒子撞击实验中,来自欧洲核子研究中心的大型强子对撞机与位
于美国伊利诺伊州巴达维亚的费米国家加速器实验室万亿电子伏特加速器(Tev
atron)都进行了研究,两台对撞机的结果都显示了接近3西格玛的水平,暗示
希格斯玻色子的质量在125千兆电子伏附近。
假设希格斯玻色子的质量在125千兆电子伏。
125 Gev = 134.1919327 u
m = A(2- n)
134.1919327 = 135(2- n)
0.9940143160 = 2- n
n = 1.005985684
n = 1 - 1
√ 1- ^2
2.005985684 = 1
√ 1- ^2
<0.867062715 C
(稳定碰撞速度上限)
 = 0.866885073 C >0.8660254038 C(形成稳定核的碰撞速度){
>0.864969723 C(稳定碰撞速度下限)
n =1.160460268
134.1919327 = 134(2 - n)
1.001432333 = 2- n
n = 0.998567666
n = 1 - 1
√ 1- ^2
1.998567666 = 1
√ 1- ^2
<0.867062715 C (稳定
碰撞速度)上限
 = 0.865818417 C< 0.8660254038 C(形成稳定核的碰撞速度){
>0.864969723 C (稳
定碰撞速度)下限
n = 1.153322274
粒子碰撞时的速度在0.865818417 C——0.866885073c 稳定核的碰撞速度0.8660254
038 C,但非常接近。
粒子碰撞时的能量在134u ----- 135u 之间质量非常接近于其原子量的整倍数。
可见所认为的希格斯玻色子是许多种不稳定的粒子中的一种而已。只是碰撞速度在稳
定碰撞速度附近,质量非常接近于其原子量而已。
要想在125Gev 附近得到稳定的所谓希格斯玻色子。那碰撞时的能
量必须在
134。1919291 u = 124.9999967 Gev 。粒子碰撞时的速度是0.8660
254 C。
或者粒子碰撞时的速度是0。968245837 C,产生负物质
参考书: Conditions For Formation Of Stable Nuclides And
The Unification Of Four Basic Interreactions
Senior Engineer Jintao Shen (沈觐陶)
国内各著名大学图书馆,美国MIT 图书馆,香港理工大学图书馆有藏书。
If this accelerator (CERN) adjust the colliding
velocity of particle or electron to V =0.86602540378
C,n=1.15470053838(a medium with index of refraction n)
and fix it..At the same time make the colloiding energy
variates from 1u(Atomic mass unit=931.5016 Mev) to 100u
or 1000u.What will it happen? It must produce any stable
nuclides or any desired elements as shown in periodic
table. That means : Human being can but know nature and
discover new phenomena but cannot produce it. That's
an old idea. Now we can make and produce any material,if
we know how to create the the stable nuclides. May be
free from resource deficient,the energy
resources,coal,oil,metals and other mineral

 

 




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