skip to content
Sequenza VI : per viola sola Preview this item
ClosePreview this item
Checking...

Sequenza VI : per viola sola

Author: Luciano Berio
Publisher: London : Universal Edition, ©1970.
Series: Classical scores library
Edition/Format:   Downloadable musical score : Document : No Linguistic ContentView all editions and formats
Rating:

(not yet rated) 0 with reviews - Be the first.

Subjects
More like this

 

Find a copy online

Links to this item

Find a copy in the library

&AllPage.SpinnerRetrieving; Finding libraries that hold this item...

Details

Additional Physical Format: Print version:
Berio, Luciano, 1925-2003.
Sequenza VI.
London : Universal Edition, ©1970 publisher catalog number
UE13726
Material Type: Document, Internet resource
Document Type: Internet Resource, Computer File, Musical Score
All Authors / Contributors: Luciano Berio
OCLC Number: 877973494
Notes: Cover title.
Instructions for performance in English and German.
Publisher's no.: UE 13726.
Description: 1 online resource (1 score (9 pages)).
Series Title: Classical scores library
Other Titles: Sequenza,
Responsibility: Luciano Berio.

Reviews

User-contributed reviews
Retrieving GoodReads reviews...
Retrieving DOGObooks reviews...

Tags

Be the first.

Similar Items

Related Subjects:(1)

Confirm this request

You may have already requested this item. Please select Ok if you would like to proceed with this request anyway.

Linked Data


Primary Entity

<http://www.worldcat.org/oclc/877973494> # Sequenza VI : per viola sola
    a schema:MediaObject, bgn:MusicScore, schema:CreativeWork ;
   library:oclcnum "877973494" ;
   library:placeOfPublication <http://dbpedia.org/resource/London> ; # London
   library:placeOfPublication <http://id.loc.gov/vocabulary/countries/enk> ;
   schema:about <http://experiment.worldcat.org/entity/work/data/47781974#Topic/viola_music> ; # Viola music
   schema:copyrightYear "1970" ;
   schema:creator <http://experiment.worldcat.org/entity/work/data/47781974#Person/berio_luciano_1925_2003> ; # Luciano Berio
   schema:datePublished "1970" ;
   schema:exampleOfWork <http://worldcat.org/entity/work/id/47781974> ; # Sequenza, no. 6
   schema:inLanguage "zxx" ;
   schema:isPartOf <http://experiment.worldcat.org/entity/work/data/47781974#Series/classical_scores_library> ; # Classical scores library
   schema:isSimilarTo <http://worldcat.org/entity/work/data/47781974#CreativeWork/sequenza_vi> ;
   schema:name "Sequenza VI : per viola sola" ;
   schema:productID "877973494" ;
   schema:publication <http://www.worldcat.org/title/-/oclc/877973494#PublicationEvent/london_universal_edition_1970> ;
   schema:publisher <http://experiment.worldcat.org/entity/work/data/47781974#Agent/universal_edition> ; # Universal Edition
   schema:url <https://grinnell.idm.oclc.org/login?url=http://www.aspresolver.com/aspresolver.asp?SHMU;554375> ;
   schema:url <http://www.aspresolver.com/aspresolver.asp?SHMU;554375> ;
   wdrs:describedby <http://www.worldcat.org/title/-/oclc/877973494> ;
    .


Related Entities

<http://dbpedia.org/resource/London> # London
    a schema:Place ;
   schema:name "London" ;
    .

<http://experiment.worldcat.org/entity/work/data/47781974#Agent/universal_edition> # Universal Edition
    a bgn:Agent ;
   schema:name "Universal Edition" ;
    .

<http://experiment.worldcat.org/entity/work/data/47781974#Person/berio_luciano_1925_2003> # Luciano Berio
    a schema:Person ;
   schema:birthDate "1925" ;
   schema:deathDate "2003" ;
   schema:familyName "Berio" ;
   schema:givenName "Luciano" ;
   schema:name "Luciano Berio" ;
    .

<http://experiment.worldcat.org/entity/work/data/47781974#Series/classical_scores_library> # Classical scores library
    a bgn:PublicationSeries ;
   schema:hasPart <http://www.worldcat.org/oclc/877973494> ; # Sequenza VI : per viola sola
   schema:name "Classical scores library" ;
    .

<http://worldcat.org/entity/work/id/47781974> # Sequenza, no. 6
   schema:name "Sequenza, no. 6" ;
    .


Content-negotiable representations

Close Window

Please sign in to WorldCat 

Don't have an account? You can easily create a free account.